3x^2-54x+50=0

Solution for 3x^2-54x+50=0 equation:

3x^2-54x+50=0

a = 3; b = -54; c = +50;
Δ = b2-4ac
Δ = -542-4·3·50
Δ = 2316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2316}=\sqrt{4*579}=\sqrt{4}*\sqrt{579}=2\sqrt{579}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-2\sqrt{579}}{2*3}=\frac{54-2\sqrt{579}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+2\sqrt{579}}{2*3}=\frac{54+2\sqrt{579}}{6}
$